Solveeit Logo

Question

Question: The angular velocity of seconds hand of a watch will be...

The angular velocity of seconds hand of a watch will be

A

π60rad/sec\frac{\pi}{60}rad/\sec

B

π30rad/sec\frac{\pi}{30}rad/sec

C

60πrad/sec60\pi rad/sec

D

30πrad/sec30\pi rad/sec

Answer

π30rad/sec\frac{\pi}{30}rad/sec

Explanation

Solution

We know that second's hand completes its revolution (2π) in 60 sec ∴ ω=θt=2π60=π30rad/sec\omega = \frac{\theta}{t} = \frac{2\pi}{60} = \frac{\pi}{30}rad ⥂ / ⥂ \sec