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Question

Physics Question on Uniform Circular Motion

The angular velocity of second hand, of a clock is :

A

(π6)rads1\left(\frac{\pi}{6}\right) rad\, s ^{-1}

B

(π60)rads1\left(\frac{\pi}{60}\right) rad\, s ^{-1}

C

(π30)rads1\left(\frac{\pi}{30}\right) rad\, s ^{-1}

D

(π15)rads1\left(\frac{\pi}{15}\right) rad\, s ^{-1}

Answer

(π30)rads1\left(\frac{\pi}{30}\right) rad\, s ^{-1}

Explanation

Solution

Angular velocity =ΔθΔt=2π60rads1=\frac{\Delta \theta}{\Delta t}=\frac{2 \pi}{60} rad\, s ^{-1} =π30rads1=\frac{\pi}{30} rad \,s ^{-1} Reason : A second hand makes an angle of 2π2 \pi (i.e., 360360^{\circ} ) is one minute, (i.e., 60s60 \,s ).