Question

The angular velocities of three bodies in simple harmonic motion are $\omega_{1},\omega_{2},\omega_{3}$ with their respective amplitudes as$A_{1},A_{2},A_{3}$. If all the three bodies have same mass and velocity, then

• A. $A_{1}\omega_{1} = A_{2}\omega_{2} = A_{3}\omega_{3}$
• B. $A_{1}{\omega_{1}}^{2} = A_{2}{\omega_{2}}^{2} = A_{3}{\omega_{3}}^{2}$
• C. ${A_{1}}^{2}\omega_{1} = {A_{2}}^{2}\omega_{2} = {A_{3}}^{2}\omega_{3}$
• D. ${A_{1}}^{2}{\omega_{1}}^{2} = {A_{2}}^{2}{\omega_{2}}^{2} = A^{2}$

Answer 1

Answer: (A)

$A_{1}\omega_{1} = A_{2}\omega_{2} = A_{3}\omega_{3}$

Answer 2

Velocity is same. So by using $v = a\omega$

⇒ $A_{1}\omega_{1} = A_{2}\omega_{2} = A_{3}\omega_{3}$