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Question: The angular speed of a motor increases from 600 rpm to 1200 rpm in 10 s. What is the angular acceler...

The angular speed of a motor increases from 600 rpm to 1200 rpm in 10 s. What is the angular acceleration of the motor

A

600radsec−2600radsec^{- 2}

B

60πradsec−260\pi radsec^{- 2}

C

60radsec−260radsec^{- 2}

D

2πradsec−22\pi radsec^{- 2}

Answer

2πradsec−22\pi radsec^{- 2}

Explanation

Solution

α=ω2−ω1t=2π(n2−n1)t=2π(1200−600)10×60radsec2\alpha = \frac{\omega_{2} - \omega_{1}}{t} = \frac{2\pi(n_{2} - n_{1})}{t} = \frac{2\pi(1200 - 600)}{10 \times 60}\frac{rad}{sec^{2}}

=2πrad/sec2= 2\pi rad/sec^{2}