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Physics Question on single slit diffraction

The angular resolution of a 10 cm diameter telescope at a wavelength of 5000 A˚\mathring{A} is of the order of

A

106rad{10}^6 rad

B

10−2rad{10}^{-2} rad

C

10−4rad{10}^{-4} rad

D

10−6rad{10}^{-6} rad

Answer

106rad{10}^6 rad

Explanation

Solution

R.P=1δθR.P = \frac{1}{\delta \theta}
The angular resolution, δθ=1.22λD\delta \theta = \frac{ 1.22 \lambda }{D}
=1.22×5000×10−80.1=6.1×10−4=10−4= \frac{ 1.22 \times 5000 \times {10}^ {-8 }}{ 0.1} = 6.1 \times {10}^{-4} = {10}^{-4}