Question

The angular momentum of the electron in first excited energy state of hydrogen atom is

• A. $\frac{h}{2\pi }$
• B. $\frac{h}{\pi }$
• C. $\sqrt{2(2+l)}\frac{h}{2\pi }$
• D. none of these

Answer 1

Answer: (B)

$\frac{h}{\pi }$

Answer 2

The angular momentum of an electron $=mvr=\frac{nh}{2\pi }$ For the first excited state $n=2$ then, $mvr=\frac{2h}{2\pi }$ $=\frac{h}{\pi }$