Question

The angular momentum of electron in 'd' orbtial is equal to

• A. $2 \sqrt{3} h$
• B. $0 \, h$
• C. $\sqrt{6} h$
• D. $\sqrt{2} h$

Answer 1

Answer: (C)

$\sqrt{6} h$

Answer 2

The correct answer is C:$\sqrt{6}h$
Orbital angular momentum = $\sqrt{\ell (\ell + 1)} . h$
for d-orbital $\ell = 2$
so orbital angular momentum = $\sqrt{2(2 + 1)} h = \sqrt{6} h$