Question

The angular momentum of electron in $3d$ orbital of an atom is

• A. $\sqrt{2} \left(\frac{h}{2\pi}\right)$
• B. $\sqrt{3} \left(\frac{h}{2\pi}\right)$
• C. $\sqrt{6} \left(\frac{h}{2\pi}\right)$
• D. $\sqrt{12} \left(\frac{h}{2\pi}\right)$

Answer 1

Answer: (C)

$\sqrt{6} \left(\frac{h}{2\pi}\right)$

Answer 2

The angular momentum is given by
$L = \sqrt{l(l+1)} \left(\frac{h}{2\pi} \right)$
For $3d$ electron, $l = 2$
$\therefore \:\:\: L = \sqrt{2(3)} \left(\frac{h}{2\pi}\right) = \sqrt{6} \left(\frac{h}{2\pi}\right)$