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Question

Chemistry Question on Organic Chemistry- Some Basic Principles and Techniques

The angle strain in cyclobutane is

A

24∘44′24^\circ 44'

B

29∘16′29^\circ 16'

C

19∘22′19^\circ 22'

D

9∘44′9^\circ 44'

Answer

9∘44′9^\circ 44'

Explanation

Solution

When carbon is bonded to four other atoms, the angle between any pair of bonds =109∘,28′=109^{\circ}, 28' (tetrahedral angle) but the ring of cyclobutane is square with four angles of 90∘90^{\circ}. So, deviation of the bond angle (angle strain) in cyclobutane =109∘28′−90∘/2=109^{\circ} 28'-90^{\circ} / 2 =19∘28%2=9∘44′=19^{\circ} 28 \% 2=9^{\circ} 44'