Question
Question: The angle of projection at which the horizontal range and maximum height of projectile are equal is...
The angle of projection at which the horizontal range and maximum height of projectile are equal is
A
45o
B
θ=tan−1(0.25)
C
θ=tan−14or (θ=76∘)
D
60o
Answer
θ=tan−14or (θ=76∘)
Explanation
Solution
R=4Hcotθ.
When R=H then cotθ=1⥂/⥂4⇒θ=tan−1(4)