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Question: The angle of polarisation for any medium is 60<sup>o</sup>, what will be critical angle for this....

The angle of polarisation for any medium is 60o, what will be critical angle for this.

A

sin⁡−13\sin^{- 1}\sqrt{3}

B

tan⁡−13\mathbf{\tan}^{\mathbf{-}\mathbf{1}}\sqrt{\mathbf{3}}

C

cos⁡−13\cos^{- 1}\sqrt{3}

D

sin⁡−113\sin^{- 1}\frac{1}{\sqrt{3}}

Answer

sin⁡−113\sin^{- 1}\frac{1}{\sqrt{3}}

Explanation

Solution

By using μ=tan⁡θp⇒μ=tan⁡60=3\mu = \tan\theta_{p} \Rightarrow \mu = \tan 60 = \sqrt{3},

Also C=sin⁡−1(1μ)⇒C=sin⁡−1(13)C = \sin^{- 1}\left( \frac{1}{\mu} \right) \Rightarrow C = \sin^{- 1}\left( \frac{1}{\sqrt{3}} \right)