Question

The angle of polarisation for any medium is 60⁰, what will be critical angle for this –

• A. sin^–1$\sqrt{3}$
• B. tan^–1$\sqrt{3}$
• C. cos^–1$\sqrt{3}$
• D. sin^–1$\frac{1}{\sqrt{3}}$

Answer 1

Answer: (D)

sin^–1$\frac{1}{\sqrt{3}}$

Answer 2

µ = tanq_p Ž µ = tan60ŗ = $\sqrt{3}$

Ž $\frac{1}{\sin c}$ = $\sqrt{3}$; c =sin^–1$\left( \frac{1}{\sqrt{3}} \right)$