Question

The angle of intersection of the curves y = 4 –x² and y = x² is

• A. p/2
• B. tan^–1$\left( \frac{4}{3} \right)$
• C. tan^–1$\frac{4\sqrt{2}}{7}$
• D. None of these

Answer 1

Answer: (C)

tan^–1$\frac{4\sqrt{2}}{7}$

Answer 2

Intersection point x² = 4– x² ̃ x =$\sqrt{2}$, y = 2

Now m₁ =$2\sqrt{2}$; m₂ = –$2\sqrt{2}$; tan q = $\left| \frac{4\sqrt{2}}{1 - 8} \right| = \frac{4\sqrt{2}}{7}$