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Question: The angle of elevation of the top of a tower from a point 20 meters away from its base is \(45 ^ { \...

The angle of elevation of the top of a tower from a point 20 meters away from its base is 45∘45 ^ { \circ }. The height of the tower is

A

10 m

B

20 m

C

40 m

D

203 m20 \sqrt { 3 } \mathrm {~m}

Answer

20 m

Explanation

Solution

Let height of the tower be h.

h20=tan⁡45∘\frac { h } { 20 } = \tan 45 ^ { \circ }