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Question

Question: The angle between two lines \(\frac { x + 1 } { 2 } =\) \(\frac { y + 3 } { 2 } = \frac { z - 4 } { ...

The angle between two lines x+12=\frac { x + 1 } { 2 } = y+32=z41\frac { y + 3 } { 2 } = \frac { z - 4 } { - 1 } and x41=y+42=z+12\frac { x - 4 } { 1 } = \frac { y + 4 } { 2 } = \frac { z + 1 } { 2 } is

A

cos1(19)\cos ^ { - 1 } \left( \frac { 1 } { 9 } \right)

B

cos1(29)\cos ^ { - 1 } \left( \frac { 2 } { 9 } \right)

C

cos1(39)\cos ^ { - 1 } \left( \frac { 3 } { 9 } \right)

D

cos1(49)\cos ^ { - 1 } \left( \frac { 4 } { 9 } \right)

Answer

cos1(49)\cos ^ { - 1 } \left( \frac { 4 } { 9 } \right)

Explanation

Solution

θ=cos1((2)(1)+(2)(2)+(1)(2)22+22+1212+22+22)=cos149\theta = \cos ^ { - 1 } \left( \frac { ( 2 ) ( 1 ) + ( 2 ) ( 2 ) + ( - 1 ) ( 2 ) } { \sqrt { 2 ^ { 2 } + 2 ^ { 2 } + 1 ^ { 2 } } \sqrt { 1 ^ { 2 } + 2 ^ { 2 } + 2 ^ { 2 } } } \right) = \cos ^ { - 1 } \frac { 4 } { 9 }.