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Question

Question: The angle between the vectors \(\vec { A }\) and \(\vec { A } \cdot ( \vec { B } \times \vec { A } )...

The angle between the vectors A\vec { A } and A(B×A)\vec { A } \cdot ( \vec { B } \times \vec { A } ) is

A

A2BA ^ { 2 } B

B

Zero

C

A2BsinθA ^ { 2 } B \sin \theta

D

A2BcosθA ^ { 2 } B \cos \theta

Answer

Zero

Explanation

Solution

Let A(B×A)=AC\vec { A } \cdot ( \vec { B } \times \vec { A } ) = \vec { A } \cdot \vec { C }

Here C=B×A\vec { C } = \vec { B } \times \vec { A } Which is perpendicular to both vector A\vec { A } and B\vec { B }AC=0\vec { A } \cdot \vec { C } = 0