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Question

Question: The angle between the two vectors\(\overrightarrow{A} = 3\widehat{i} + 4\widehat{j} + 5\widehat{k}\)...

The angle between the two vectorsA=3i^+4j^+5k^\overrightarrow{A} = 3\widehat{i} + 4\widehat{j} + 5\widehat{k}and B=3i^+4j^+5k^\overrightarrow{B} = 3\widehat{i} + 4\widehat{j} + 5\widehat{k} is

A

60°

B

Zero

C

90°

D

None of these

Answer

None of these

Explanation

Solution

cosθ=A.BAB=9+16+259+16+259+16+25\cos\theta = \frac{\overset{\rightarrow}{A}.\overset{\rightarrow}{B}}{|A||B|} = \frac{9 + 16 + 25}{\sqrt{9 + 16 + 25}\sqrt{9 + 16 + 25}}=5050=1\frac{50}{50} = 1

cosθ=1\cos\theta = 1 \therefore θ=cos1(1)\theta = \cos^{- 1}(1)