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Question: The angle between the tangents at the ends of a focal chord of a parabola is A.\[90^\circ \] B.\...

The angle between the tangents at the ends of a focal chord of a parabola is
A.9090^\circ
B.4545^\circ
C.6060^\circ
D.N.O.T.

Explanation

Solution

Hint: We will use the standard equation of a parabola to find the angle between the tangents at the ends of a focal chord of a parabola. We have to find the product of the slopes of the tangents in order to find the angle.

Complete step-by-step answer:
A chord of a parabola which passes through its focus is called a focal chord of the parabola. A parabola is formed when the constant ratio eccentricity is equals to 1.
Let us assume  y2=4ax\;{y^2} = 4ax to be the standard equation of a parabola.
We will let P(at12,2at1)P(at_1^2,2a{t_1}) and Q(at22,2at2)Q(at_2^2,2a{t_2}) be two points on the curve.
The equation of PQ will therefore be (y2at1)=2t1+t2(xat12)(y - 2a{t_1}) = \dfrac{2}{{{t_1} + {t_2}}}\left( {x - at_1^2} \right)
As PQ is a focal chord, it passes through S(a,0)S(a,0),

2at1=2t1+t2(aat12) 2at1(t1+t2)=2(aat12) 2at122at1t2=2a2at12 2at1t2=2a t1t2=1  \Rightarrow - 2a{t_1} = \dfrac{2}{{{t_1} + {t_2}}}(a - at_1^2) \\\ \Rightarrow - 2a{t_1}({t_1} + {t_2}) = 2(a - at_1^2) \\\ \Rightarrow - 2at_1^2 - 2a{t_1}{t_2} = 2a - 2at_1^2 \\\ \Rightarrow - 2a{t_1}{t_2} = 2a \\\ \Rightarrow {t_1}{t_2} = - 1 \\\

We will now let m1&m2{m_1}\& {m_2}be the slopes of the tangents P and Q respectively.
m1m2=t1t2=1{m_1}{m_2} = {t_1}{t_2} = - 1
Therefore, the angle between the tangents at the ends of the focal chord of the parabola is 9090^\circ because if the product of two slopes is 1 - 1, then the two lines are said to be perpendicular.
Thus, the answer is option A.

Note: This question is an observation from a close examination of the four standard equations of the parabola and the results derived in relation to them. We have assumed the equation of the parabola to be   y2=4ax\;{y^2} = 4ax where the origin is the vertex and the x-axis is the axis of the parabola.