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Question

Physics Question on Centre of mass

The angle between the linear momentum and angular momentum of a particle moving along a circle is

A

00^{\circ}

B

4545^{\circ}

C

9090^{\circ}

D

180180^{\circ}

Answer

9090^{\circ}

Explanation

Solution

The angular momentum of a particle moving along a circle of radius rr is
L=r×p\vec{L}=\vec{r}\times\vec{p} where p\vec{p} is the linear momentum of the particle
By the definition of vector product, L\vec{L} is perpendicular to p\vec{p}.
So the angle between them is 9090^{\circ}.