Question

The angle between the line $\frac{x - 2}{a} = \frac{y - 2}{b} = \frac{z - 2}{c}$ and the plane $ax + by + cz + 6 = 0$ is

• A. $\sin^{- 1}\left( \frac{1}{\sqrt{a^{2} + b^{2} + c^{2}}} \right)$
• B. $45^{o}$
• C. $60^{o}$
• D. $90^{o}$

Answer 1

Answer: (D)

$90^{o}$

Answer 2

Obviously the line perpendicular to the plane because $\frac { a } { a } = \frac { b } { b } = \frac { c } { c }$ i.e., their direction ratios are proportional.