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Question

Mathematics Question on Hyperbola

The angle between the asymptotes of the hyperbola x2−3y2=12x^2 - 3y^2 = 12 is

A

0∘0^{\circ}

B

60∘60^{\circ}

C

30∘30^{\circ}

D

15∘15^{\circ}

Answer

60∘60^{\circ}

Explanation

Solution

We have x2−3y2=12⇒   x212−y24=1x^2 - 3y^2 = 12 \Rightarrow \:\:\: \frac{x^{2}}{12} - \frac{y^{2}}{4} = 1
Angle between assymptotes is given by 2tan⁡−1(ba)=2×30∘=60∘2\tan^{-1} \left(\frac{b}{a}\right) = 2 \times30^{\circ} = 60^{\circ}