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Question

Physics Question on Displacement current

The amplitude of the sinusoidially oscillating electric field of a plane wave is 60V/m60\, V/m . Then the amplitude of magnetic field is:

A

2×102T2\times {{10}^{2}}T

B

6×107T6\times {{10}^{7}}T

C

6×102T6\times {{10}^{2}}T

D

2×107T2\times {{10}^{-7}}T

Answer

2×107T2\times {{10}^{-7}}T

Explanation

Solution

The instantaneous magnitudes of electric field (E) and magnetic field (B) are related as
EB=c\frac{E}{B}=c \Rightarrow B=EcB=\frac{E}{c}
Given, E=60V/m,c=3×108m/sE=60\,V/m,c=3\times {{10}^{8}}m/s
\therefore B=603×108=2×107TB=\frac{60}{3\times {{10}^{8}}}=2\times {{10}^{-7}}T