Question

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is $B_0 = 510\ nT$. What is the amplitude of the electric field part of the wave?

Answer 1

Amplitude of magnetic field of an electromagnetic wave in a vacuum,
$B_0 = 510\ nT = 510 \times 10^{−9} T$
Speed of light in a vacuum, $c = 3 × 10^8 m/s$
Amplitude of electric field of the electromagnetic wave is given by the relation,
$E = cB_0$
$E = 3 × 10^8 × 510 × 10^{−9 }$
$E = 153 \ N/C$

Therefore, the electric field part of the wave is $153\ N/C$.