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Question: The amplitude of the magnetic field of a harmonic electromagnetic wave in vacuum is \(B_{0} = 510nT....

The amplitude of the magnetic field of a harmonic electromagnetic wave in vacuum is B0=510nT.B_{0} = 510nT. The amplitude of the electric field part of the wave is:

A

120NC−1120NC^{- 1}

B

134NC−1134NC^{- 1}

C

150NC−1150NC^{- 1}

D

153NC−1153NC^{- 1}

Answer

153NC−1153NC^{- 1}

Explanation

Solution

: Here, B0=510nT=510×10−9TB_{0} = 510nT = 510 \times 10^{- 9}T

E0=cB0=3×108×510×10−9=153NC−1E_{0} = cB_{0} = 3 \times 10^{8} \times 510 \times 10^{- 9} = 153NC^{- 1}