Question

The amplitude of a particle executing S.H.M. with frequency of 60 Hz is 0.01 m. The maximum value of the acceleration of the particle is

• A. $144\pi^{2}m/ ⥂ sec^{2}$
• B. $144m/ ⥂ sec^{2}$
• C. $\frac{144}{\pi^{2}}m/ ⥂ sec^{2}$
• D. $288\pi^{2}m/ ⥂ sec^{2}$

Answer 1

Answer: (A)

$144\pi^{2}m/ ⥂ sec^{2}$

Answer 2

Maximum acceleration

$= a\omega^{2} = a \times 4\pi^{2}n^{2}$

$= 0.01 \times 4 \times (\pi)^{2} \times (60)^{2} = 144\pi^{2}m/\sec$