Question

The amplitude of a particle executing SHM is $3 \,cm$ The displacement at which its kinetic energy will be $25 \%$ more than the potential energy is:_______ $cm$

Answer 1

The correct answer is 2.
KE=PE+4PE​
KE=45​PE
21​mω2(A2−x2)=45​×21​mω2x2
[v=ωA2−x2​]
A2−x2=45​x2
49x2​=A2
x=32​A
∴x=32​×3cm
x=2cm