Question: The amount of urea to be dissolved in 500 ml of water (K =18.6 K $mole^{- 1}$in 100g solvent) to p...

Question

The amount of urea to be dissolved in 500 ml of water (K =18.6 K $mole^{- 1}$ in 100g solvent) to produce a depression of $0.186^{o}C$ in freezing point is.

Answer 1

Solution

$\Delta T_{f} = \frac{100 \times K \times w}{m \times W}$ $\therefore 0.186 = \frac{100 \times 18.6 \times w}{60 \times 500}$

$w = 3g$

Question: The amount of urea to be dissolved in 500 ml of water (K =18.6 K \(mole^{- 1}\)in 100g solvent) to p...

Solution