Question

The amount of sugar ${(C_{12}H_{22}O_{11})}$ required to prepare $2\, L$ of its $0.1\, M$ aqueous solution is :

• A. 68.4 g
• B. 17.1 g
• C. 34.2g
• D. 136.8 g

Answer 1

Answer: (A)

68.4 g

Answer 2

$Molarity = \frac{\left(n\right)_{\text{solute}}}{V_{\text{solution}} \left(\text{in} \text{lit}\right)}$ $0.1 = \frac{wt. /342}{2}$ $wt\left(C_{12}H_{22}O_{11}\right) = 68.4\, \text{gram}$