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Question

Question: The amount of heat required to change \(1kg\) of ice to water without a change in temperature is cal...

The amount of heat required to change 1kg1kg of ice to water without a change in temperature is called as:
A. specific latent heat of evaporation
B. specific latent heat of fusion
C. latent heat of evaporation
D. latent heat of fusion

Explanation

Solution

Here we can see that there is phase reversal happening. The specific latent heat of fusion of a material is the measure of energy required to vary the state of 1 kg of the material without making any change in its temperature. These all will help us to solve this question.

Complete step-by-step answer:
Here we have to discuss the specific latent heat of fusion as well as vaporisation and also latent heat of fusion as well as vaporisation. Latent heat of evaporation is defined as the energy released or absorbed by an object or a system in thermodynamics by changing the phase from liquid state to vapour state during an isothermal process. It is also called the heat of transformation.
A specific latent heat of evaporation is the amount of energy in the form of heat which is required to completely make a phase change of a unit mass of a substance from liquid state to vapour state.
Latent heat of evaporation is explained as the heat energy is required to go into a substance to vary it from a solid into a melted liquid without any raise in temperature.
Specific latent heat of fusion is explained as the energy required to change the solid state into liquid state without changing the temperature of the unit mass of the substance. Therefore from this we can see that the specific latent heat of fusion is the correct answer for this question.

So, the correct answer is “Option B”.

Note: The specific heat is expressed as an intensive property. Intensive properties are the characteristics of material which are not dependent on the size of the material. Therefore the specific heat is an example for this and its unit is expressed as energy per kilogram.