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Question

Chemistry Question on Thermodynamics

The amount of heat released when 20mL20\, mL of 0.5MNaOH0.5 \,M \,NaOH is mixed with 100mL100 \,mL of 0.1MHCl0.1 \,M \,HCl is xkJx \,kJ. The heat of neutralisation (in kJmol1kJ \,mol ^{-1} ) is

A

-100 x

B

-50 x

C

#ERROR!

D

#ERROR!

Answer

-100 x

Explanation

Solution

Equivalents of NaOH=20×0.51000=0.01N a O H=\frac{20 \times 0.5}{1000}=0.01 Equivalents of HCl=100×0.11000=0.01H C l=\frac{100 \times 0.1}{1000}=0.01 0.010.01 equivalents, of acid and base release heat =xkJ=-x\, k J 1\therefore 1 equivalents of acid and base release heat =x0.0.1×1=100xkJ=\frac{-x}{0.0 .1} \times 1=-100\, x\, k J