Question

The amount of heat evolved when $500 \,cm^3$ of $0.1 \,M \,HCl$ is mixed with $200\, cm^3$ of $0.2\,M \,NaOH$ is _______

• A. $1.292\, kJ$
• B. $2.292\, kJ$
• C. $3.392\, kJ$
• D. $0.292\, kJ$

Answer 1

Answer: (B)

$2.292\, kJ$

Answer 2

$\because$ In neutralisation of 1 mole of $NaOH$ by 1 mole HCl, heat evolved $=57.3\, kJ$
$\therefore$ To neutralise $0.04$ mole of $NaOH$ by

$0.04$ mole of $HCl,$

heat evolved will be $=57.3 \times 0.04\, kJ$
$=2.292\, kJ$