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Question: The amount of heat evolved when \(0.50\) mole of HCl is mixed with \(0.30mole\) of NaOH solution is...

The amount of heat evolved when 0.500.50 mole of HCl is mixed with 0.30mole0.30mole of NaOH solution is

A

57.1kJ57.1kJ

B

28.55kJ28.55kJ

C

11.42kJ11.42kJ

D

17.13kJ17.13kJ

Answer

17.13kJ17.13kJ

Explanation

Solution

: 0.500.50mol of HCl 0.50\equiv 0.50 mol of H+H^{+}

0.300.30 mol of NaOH 0.30\equiv 0.30 mol of OHOH^{-}

H++OHH2OH^{+} + OH^{-} \rightarrow H_{2}O (Neutralisation)

0.300.30 mol of HCl 0.30\equiv 0.30 mol of H+H^{+}

or 0.300.30 mol of H+0.30H^{+} \equiv 0.30 mol of OHOH^{-}

Heat evolved with 1 mol H+=57.1kJH^{+} = 57.1kJ

Heat evolved with 0.300.30 mol

H+=87.1×0.30=17.13kJH^{+} = 87.1 \times 0.30 = 17.13kJ