Question

The amount of charge required to liberate 9 gm of aluminium (atomic weight = 27 and valency = 3) in the process of electrolysis is (Faraday's number = 96500 coulombs/gm equivalent)

• A. 321660 coulombs
• B. 69500 coulombs
• C. 289500 coulombs
• D. 96500 coulombs

Answer 1

Answer: (D)

96500 coulombs

Answer 2

Equivalent weight of aluminium $= \frac{27}{3} = 9$

So 1 faraday = 96500 C are required to liberate 9 gm of Al.