Solveeit Logo
Login

Question

Question: The amount of anhydrous \(\mathrm { Na } _ { 2 } \mathrm { CO } _ { 3 }\) present in 250 ml of 0.25 ...

The amount of anhydrous Na2CO3\mathrm { Na } _ { 2 } \mathrm { CO } _ { 3 } present in 250 ml of 0.25 M solution is.

A

6.225 g

B

66.25 g

C

6.0 g

D

6.625 g

Answer

6.625 g

Explanation

Solution

M=wm×V(l)M = \frac { w } { m \times V ( l ) } ; 0.25=w106×0.250.25 = \frac { w } { 106 \times 0.25 };w=6.625w = 6.625 gm