Question

The amount of acetic acid present in $100ml$ of $0.1M$ solution is:
$1)0.30g$
$2)3.0g$
$3)0.60g$
$4)none$

Answer 1

We will use a formula to find the amount of acetic acid present in $100ml$ of $0.1M$ solution. The molar mass of acetic acid should be known in advance to use this formula. A simple calculation will be needed to solve the overall question.

Complete step by step answer:
We know that, Molar mass of acetic acid is $60g/mol$.
Which we will use in the next equation.
Here, we will use the equation as
$Molarity$ $=$ $(mass \times 1000) \div (Molar Mass \times V)$
Here, $mass$ = $unknown$
Molarity$$$$ = $0.1M$
MolarMass$$$$ = $60g/mol$
$V$ $=$ Volume in $ml$ $=$ $100ml$
These three values are given in the question.
By putting this values in above equation,
0.1$$$$ = $(mass \times 1000) \div (60 \times 100)$
Putting mass on left side and other values on right side, we get,
Mass $=$ $(0.1 \times 60 \times 100) \div 1000$
Therefore, Mass $=$ 0.60g
Thus, option $3)0.60g$ will be the correct answer.

Additional information:
Formula of acetic acid is $CH_3COOH$. We can calculate molar mass of acetic acid using this equation also.
That is by adding molar mass of individual elements in the formula of acetic acid.
Molar mass is defined as mass in grams of $1$ mole of the substance.
Molarity is defined as the concentration of solution expressed as the number of moles of solute per litre solution.
The formula used in the above answer can be used to solve many equations.
Only when we have provided all other values and we have to find value in only one quantity.

Note:
The molar mass of a substance is the mass in grams of 1 mole of the substance. We can obtain a substance's molar mass by summing the molar masses of its component atoms. We can then use the calculated molar mass to convert between mass and number of moles of the substance.