Question
Mathematics Question on Complex Functions
The all values of z, such that
√2 sin z = coshβ + isinħβ, where β is real, are
A
z=(2n+1)2π+(−1)n(4π+iβ),n=0,±1,±2,.......
B
z=nπ−(−1)n(43π+iβ),n=0,±1,±2,.......
C
z=nπ+(−1)n(4π+iβ),n=0,±1,±2,.......
D
z=(2n+1)2π+(−1)n(2π+iβ),n=0,±1,±2,.......
Answer
z=nπ+(−1)n(4π+iβ),n=0,±1,±2,.......
Explanation
Solution
The correct answer is(C): z=nπ+(−1)n(4π+iβ),n=0,±1,±2,.......