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Question

Mathematics Question on Complex Functions

The all values of z, such that
√2 sin z = coshβ + isinħβ, where β is real, are

A

z=(2n+1)π2+(1)n(π4+iβ),n=0,±1,±2,.......z=(2n+1)\frac{\pi}{2}+(-1)^n(\frac{\pi}{4}+i\beta), n=0,\pm1,\pm2,.......

B

z=nπ(1)n(3π4+iβ),n=0,±1,±2,.......z=n\pi-(-1)^n(\frac{3\pi}{4}+i\beta), n=0,\pm1,\pm2,.......

C

z=nπ+(1)n(π4+iβ),n=0,±1,±2,.......z=n\pi+(-1)^n(\frac{\pi}{4}+i\beta), n=0,\pm1,\pm2,.......

D

z=(2n+1)π2+(1)n(π2+iβ),n=0,±1,±2,.......z=(2n+1)\frac{\pi}{2}+(-1)^n(\frac{\pi}{2}+i\beta), n=0,\pm1,\pm2,.......

Answer

z=nπ+(1)n(π4+iβ),n=0,±1,±2,.......z=n\pi+(-1)^n(\frac{\pi}{4}+i\beta), n=0,\pm1,\pm2,.......

Explanation

Solution

The correct answer is(C): z=nπ+(1)n(π4+iβ),n=0,±1,±2,.......z=n\pi+(-1)^n(\frac{\pi}{4}+i\beta), n=0,\pm1,\pm2,.......