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Question: The ages of two sisters are \[11\] years and \[14\] years. In how many years of time will the produc...

The ages of two sisters are 1111 years and 1414 years. In how many years of time will the product of their ages be 304304?

Explanation

Solution

The accurate solution follows the concept of quadratic equations. By the use of quadratic equations, the equation can be solved very easily. The use of quadratic equations will help everyone to get through this simple question. Now let’s just solve the question through quadratic equations.

Complete step-by-step solution:
According to the question, the age of both the sisters is 1111 years and 1414 years respectively.
So, now assume after x years the product of their ages be taken as (11+x)(14+x)(11 + x)\left( {14 + x} \right):
Therefore, we start with the equation:
(11+x)(14+x)=304\Rightarrow (11 + x)\left( {14 + x} \right) = 304
154+11x+14x+x2=304\Rightarrow 154 + 11x + 14x + {x^2} = 304
x2+25x150=0\Rightarrow {x^2} + 25x - 150 = 0
(x+30)(x5)=0\Rightarrow \left( {x + 30} \right)(x - 5) = 0
x=30,5\Rightarrow x = - 30,5
Therefore, we can see that there are two results of xx. But we have to calculate the number of years, and according to the result, there are two values. One is 30 - 30, and as we know that years cannot come in negative values. So, this answer is not acceptable. The second one is 55, which is a positive number, and hence is acceptable.
Therefore, in 55years, the product of their ages will be 304304.

Note: Quadratic equations can be defined as the equation where the power of the variable is square so it can be written as x2{x^2}. It is very easy to solve a quadratic equation, and it is commonly written as (ax2+bx+c=0a{x^2} + bx + c = 0) , the quadratic equation in ‘x’ is an equation that can be written in a standard form, where ‘a’ ‘b’ ‘c’ are real numbers and a0a \ne 0. Here we could also use the quadratic formula and completing the square method to solve the quadratic equation.