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Question: The adjacent sides of a rectangle with given perimeter as 100 cm and enclosing maximum area are...

The adjacent sides of a rectangle with given perimeter as 100 cm and enclosing maximum area are

A

10 cm and 40 cm

B

20 cm and 30 cm

C

25 cm and 25 cm

D

15 cm and 35 cm

Answer

25 cm and 25 cm

Explanation

Solution

2x+2y=1002x + 2y = 100x+y=50x + y = 50 .....(i)

Let area of rectangle is A, \therefore A=xyA = xyy=Axy = \frac{A}{x}

From (i), x+Ax=50x + \frac{A}{x} = 50A=50xx2A = 50x - x^{2}dAdx=502x\frac{dA}{dx} = 50 - 2x

for maximum area dAdx=0\frac{dA}{dx} = 0

\therefore 502x=050 - 2x = 0x=25x = 25 and y=25y = 25

\therefore adjacent sides are 25 cm and 25 cm.