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Question

Physics Question on Resistance

The actual value of resistance RR, shown in the figure is 30Ω30 \Omega . This is measured in an experiment as shown using the standard formula R=VIR = \frac{V}{I} , where VV and II are the readings of the voltmeter and ammeter, respectively. If the measured value of RR is 5%5\% less, then the internal resistance of the voltmeter is :

A

350 Ω\Omega

B

570 Ω\Omega

C

35 Ω\Omega

D

600 Ω\Omega

Answer

570 Ω\Omega

Explanation

Solution

0.95R=RRvR+Rv0.95 R = \frac{RR_{v}}{R+R_{v}}
0.95×30=0.05Rv0.95 \times30 = 0.05 R_{v}
Rv=19×30=570ΩR_{v} = 19 \times30 = 570\, \Omega