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Question: The activity per ml of a solution of radioactive substance is x. How much water be added to 200 ml o...

The activity per ml of a solution of radioactive substance is x. How much water be added to 200 ml of this solution so that the activity falls to x/20 per ml after 4 half-lives ?

A

100 ml

B

150 ml

C

80 ml

D

50 ml

Answer

50 ml

Explanation

Solution

N = N0(12)n \text{N = }\text{N}_{0}\left( \frac{1}{2} \right)^{n}\text{ }

(xv20)=(x)×200(12)4\left( \frac{xv}{20} \right) = (x) \times 200\left( \frac{1}{2} \right)^{4}

V = 250 ml.

So added volume of water = 50 ml.