Question

The activity of a radioactive sample is 1.6 curie and its half-life is 2.5 days. Its activity after 10 days will be –

• A. 0.8 curie
• B. 0.4 curie
• C. 0.1 curie
• D. 0.16 curie

Answer 1

Answer: (C)

0.1 curie

Answer 2

R₀ = 1.6 Ci

T_1/2 = 2.5 day, t = 10 day ̃ n = = 4

R = = $\frac { 1.6 } { 16 }$= 0.1 Ci