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Chemistry Question on Chemical Reactions of Aldehydes Ketones and Carboxylic Acids

The activation energy of one of the reactions in a biochemical process is 532611 J mol–1. When the temperature falls from 310 K to 300 K, the change in rate constant observed is k300 = x × 10–3 k310. The value of x is ______.

[Given: ln10 = 2.3, R = 8.3 JK–1 mol–1]

Answer

The correct answer is: 1

K310K300=103⇒\frac{K_{310}}{K_{300}}=10^3⇒ K30=1×10−1×K310K_{30}=1×10^{-1}×K_{310}