Question

The activation energy for a reactions is 9.0 kcal/mol. The increase in the rate constant when its temperature is increased from 298 K to 308 K is -

• A. 10%
• B. 100%
• C. 50%
• D. 63%

Answer 1

Answer: (D)

63%

Answer 2

log$\frac{K_{2}}{K_{1}} = \frac{Ea}{2.303R}\left\lbrack \frac{T_{2} - T_{1}}{T_{1}T_{2}} \right\rbrack$