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Question: The acceleration of block which is placed on a horizontal smooth fixed surface when the force F = 4m...

The acceleration of block which is placed on a horizontal smooth fixed surface when the force F = 4mg is applied on it in the direction shown in figure is –

A

g

B

232 \sqrt { 3 } g

C

2g

D

None of these

Answer

None of these

Explanation

Solution

F sinq – mg = may and F cosq = max

a = ax2+ay2\sqrt { a _ { x } ^ { 2 } + a _ { y } ^ { 2 } }