Question

The acceleration of an electron in an electric field of magnitude 50 V/cm, if e/m value of the electron is $1.76 \times 10^{11}$C/kg, is

• A. $8.8 \times 10^{14}$m/sec²
• B. $6.2 \times 10^{13}$ m/sec²
• C. $5.4 \times 10^{12}$ m/sec²
• D. Zero

Answer 1

Answer: (A)

$8.8 \times 10^{14}$m/sec²

Answer 2

$a = \frac{eE}{m} \Rightarrow a = 1.76 \times 10^{11} \times 50 \times 10^{2}$ $= 8.8 \times 10^{14}m ⥂ / ⥂ sec^{2}$