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Question: The acceleration of a particle is increasing linearly with time t as βt. If the particle starts from...

The acceleration of a particle is increasing linearly with time t as βt. If the particle starts from origin with initial velocity u, the distance travelled by it in t second is

A

ut + 1/2 βt3

B

ut + 1/4 βt3

C

ut + 1/3 βt3

D

ut + βt3/6

Answer

ut + βt3/6

Explanation

Solution

Using the relation,

S = ut + k(n+1)(n+2)tn+2\frac { \mathrm { k } } { ( \mathrm { n } + 1 ) ( \mathrm { n } + 2 ) } \mathrm { t } ^ { \mathrm { n } + 2 }

For non – uniform accelerated motion, we get

S = ut + β(1+1)(1+2)t1+2\frac { \beta } { ( 1 + 1 ) ( 1 + 2 ) } \mathrm { t } ^ { 1 + 2 }

(There a = βt so comparing it with a = ktn we get n = 1)

∴ S = ut + βt3/6