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Question

Question: The acceleration due to gravity near the surface of a planet of radius R and density d is proportion...

The acceleration due to gravity near the surface of a planet of radius R and density d is proportional to

A

dR2\frac { d } { R ^ { 2 } }

B

dR2d R ^ { 2 }

C

dR

D

dR\frac { d } { R }

Answer

dR

Explanation

Solution

g=43πρGRgdRg = \frac { 4 } { 3 } \pi \rho G R \Rightarrow g \propto d R