Question

The acceleration due to gravity at a place is$\pi^{2}m ⥂ / ⥂ sec^{2}$. Then the time period of a simple pendulum of length one metre is

• A. $\frac{2}{\pi}\sec$
• B. $2\pi sec$
• C. $2sec$
• D. $\pi sec$

Answer 1

Answer: (C)

$2sec$

Answer 2

$T = 2\pi\sqrt{l/g} = 2\pi\sqrt{\frac{1}{\pi^{2}}}$= 2 sec