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Question

Physics Question on Motion in a straight line

The acceleration due to gravity at a place is \({g = 9.61\, m \, s^{-2}}). The speed with which a ball must be thrown vertically upward from the ground level so that it reached a maximum height of 50 m is

A

\({28\, m \, s^{-2}})

B

\({30\, m \, s^{-2}})

C

\({31\, m \, s^{-2}})

D

\({29\, m \, s^{-2}})

Answer

31ms2{31\, m \, s^{-2}}

Explanation

Solution

Given hh = 50 m
aa = - g = -9.8 m s2^{-2} and vv = 0
For vertically upward motion
v2=u22ghv^2 = u^2 - 2gh
u=2gh=19.6×50=31.30ms1{u = \sqrt{2gh} = \sqrt{19.6 \times 50} = 31.30 \, m s^{-1}}