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Question

Physics Question on Escape Speed

The acceleration due to gravity at a height 1km1\, km above the earth is the same as at a depth dd below the surface of earth. Then :

A

d=1kmd = 1 km

B

d=32kmd = \frac{3}{2} km

C

d=2kmd = 2 k m

D

d=12km d = \frac{1}{2} km

Answer

d=2kmd = 2 k m

Explanation

Solution

Above earth surface
g=g(12hRe)g'=g\left(1-\frac{2 h}{R_{e}}\right)
Δg=g2hRe\Delta g'=g \frac{2 h}{R_{e}}...(1)
From (1) & (2)
d=2hd=2 h
d=2×1kmd=2 \times 1\, km
Below earth surface
g=g(1dRe)g'=g\left(1-\frac{d}{R_{e}}\right)
Δg=gdRe\Delta g=g \frac{d}{R_{e}}...(2)